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For the normal eye, the cornea of eye provides a converging power of 40D and the least converging power of the eye lens behind the cornea is 20D. Using this information, the distance between the retina and the eye lens of the eye can be estimated to be:
Options
(a) 2.5 cm
(b) 1.67 cm
(c) 1.5 cm
(d) 5 cm
Correct Answer:
2.5 cm
Explanation:
1/f = 1/v – 1/u
= 1/ 1 / 40 = 1/u
u = 1/40 m = 2.5 m
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Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A neutron is moving with a velocity u.It collides head on and elastically with an atom
- A ball is projected upwards from the foot of a tower. The ball crosses the top
- In a photoelectric effect experiment, the slope of the graph between the stopping
- When an α-particle of mass m moving with velocity ν bombards on a heavy nucleus
- A wave travelling in the +ve x-direction having displacement along y-direction as 1m
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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