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Which of the following will not undergo Hell-Volhard-Zelinsky reaction
Options
(a) Acetic acid
(b) Formic acid
(c) Propionic acid
(d) 2-Methyl propionic acid
Correct Answer:
Formic acid
Explanation:
Carboxylic acid which contain α – hydrogen atom reacts with chlorine or bromine in presence of red phosphorus to give α – chloro or α – bromo acids. This reaction is called H.V.Z (Hell Volhard Zelinsky ) reaction. CH₃COOH → CCl₃COOH(trichloroacetic acid). CH₃CH₂COOH → CH₃CBr₂COOH (α,α-dibromopropionic acid) Due to absence of α – H atom HCOOH does not undergo HVZ reaction.
Related Questions: - When excess ammonia is added to CuSO₄ solution the deep blue complex obtained is
- The coordination number of a metal in coordination compounds is
- The spin only magnetic moment of [CrF₆]⁴⁻ (atomic number for Cr is 24) is
- Benzenamine reacts with excess bromine to produce
- The hybridisation of carbon in diamond ,graphite and acetylene is in the order of
Topics: Aldehydes Ketones and Carboxylic Acid
(89)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When excess ammonia is added to CuSO₄ solution the deep blue complex obtained is
- The coordination number of a metal in coordination compounds is
- The spin only magnetic moment of [CrF₆]⁴⁻ (atomic number for Cr is 24) is
- Benzenamine reacts with excess bromine to produce
- The hybridisation of carbon in diamond ,graphite and acetylene is in the order of
Topics: Aldehydes Ketones and Carboxylic Acid (89)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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