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Oxidation number of chromium in Na₂Cr₂O₇ is
Options
(a) 2
(b) 4
(c) 3
(d) 6
Correct Answer:
6
Explanation:
Oxidation number of chromium in Na₂Cr₂O₇ is +6. Oxidation number of Na = +1. Oxidation number of O = -2. Therefore 2 + 2x -2 * 7 = 0.⇒ 2x – 12 = 0 , ⇒ x = +6.
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Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- At S.T.P the density of CCl₄ vapours in g/L will be nearest to
- The reaction of phenol with alkaline chloroform gives salicylaldehyde, it is
- Which of the esters shown, after reduction with LiAlH₄ and aqueous workup, will
- The two electrons in K-subshell will differ in
- A device that converts energy of combustion of fuels like hydrogen and methane,
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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