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Oxidation number of chromium in Na₂Cr₂O₇ is
Options
(a) 2
(b) 4
(c) 3
(d) 6
Correct Answer:
6
Explanation:
Oxidation number of chromium in Na₂Cr₂O₇ is +6. Oxidation number of Na = +1. Oxidation number of O = -2. Therefore 2 + 2x -2 * 7 = 0.⇒ 2x – 12 = 0 , ⇒ x = +6.
Related Questions: - A neutral fertilizer among these compounds is
- Which will show geometrical isomerism
- Which one of the following is not a sulphide ore
- The oxidation states of S atoms in S₄O₆²⁻ from left to right respectively
- The values of heat of formation of SO₂ and SO₃ are -298.2 kJ and -98.2 kJ.
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A neutral fertilizer among these compounds is
- Which will show geometrical isomerism
- Which one of the following is not a sulphide ore
- The oxidation states of S atoms in S₄O₆²⁻ from left to right respectively
- The values of heat of formation of SO₂ and SO₃ are -298.2 kJ and -98.2 kJ.
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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