| ⇦ |
| ⇨ |
What is the magnetic moment for Mn²⁺ ion in low spin state
Options
(a) 5.90 BM
(b) 8.90 BM
(c) 2.8 BM
(d) 1.73 BM
Correct Answer:
1.73 BM
Explanation:
For Mn²⁺ ion in low spin state, number of unpaired electrons = 1. Magnetic moment = √n(n+2) =√1*3=1.73 BM.
Related Questions: - If the hydrogen ion concentration of an acid decreases 10 times, its pH value
- Ethyl alcohol exhibits acidic character on reacting with
- The number of moles of KMnO₄ reduced by one mole of KI in alkaline medium is
- The presence of colloidal particles can be confirmed with the help of
- The smallest among the following ion is
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the hydrogen ion concentration of an acid decreases 10 times, its pH value
- Ethyl alcohol exhibits acidic character on reacting with
- The number of moles of KMnO₄ reduced by one mole of KI in alkaline medium is
- The presence of colloidal particles can be confirmed with the help of
- The smallest among the following ion is
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply