| ⇦ | 
| ⇨ |
In Ramsay and Rayleigh’s isolation on noble gases from air, the nitrogen of the air is finally converted into
Options
(a) NaNO₂ only
(b) NO and NO₂
(c) NaNO₃ only
(d) NaNO₂ and NaNO₃
Correct Answer:
NaNO₂ and NaNO₃
Explanation:
Nitrogen is finally converted into NaNO₂ and NaNO₃, in Ramsay and Rayleigh’s method. N₂ + O₂ → 2NO. 2NO + O₂ → 2NO₂. 2NO₂ + 2NaOH → NaNO₂ + NaNO₃ + H₂O.
Related Questions: - What is the volume of ’20 volume H₂O₂. required to get 5000 cm³ of oxygen at STP?
- An organic compound A(C₄H₉Cl) on reaction with Na/diethylether gives a hydrocarbon
- According to IUPAC nomenclature sodium nitroprusside is named as
- The unit in which the solubility product of barium phosphate is expressed as
- Aluminium (III) chloride forms a dimer because aluminium
Topics: P Block Elements in Group 15
(89)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the volume of ’20 volume H₂O₂. required to get 5000 cm³ of oxygen at STP?
- An organic compound A(C₄H₉Cl) on reaction with Na/diethylether gives a hydrocarbon
- According to IUPAC nomenclature sodium nitroprusside is named as
- The unit in which the solubility product of barium phosphate is expressed as
- Aluminium (III) chloride forms a dimer because aluminium
Topics: P Block Elements in Group 15 (89)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply