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In the electrolysis of water, one faraday of electrical energy would evolve
Options
(a) one mole of oxygen
(b) one g atom of oxygen
(c) 8 g of oxygen
(d) 22.4 litres of oxygen
Correct Answer:
8 g of oxygen
Explanation:
Hydrolysis of water can be represented by the following equations: 2H₂O ⇌ O₂ + 4H⁺ + 4e⁻. 4 Faraday of charge liberate O₂ = 32 g. Therefore 1 Faraday of charge liberate O₂ = 32/4 = 8g.
Related Questions: - Which of the following is isoelectronic?
- The IUPAC name for Co(NH₃)₆Cl₃ is
- The vacant space in bcc lattice unit cell is
- For vaporization of water at 1 atmospheric pressure, the values of ΔH and ΔS
- Oxidation number of carbon in CH₂Cl₂ is
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is isoelectronic?
- The IUPAC name for Co(NH₃)₆Cl₃ is
- The vacant space in bcc lattice unit cell is
- For vaporization of water at 1 atmospheric pressure, the values of ΔH and ΔS
- Oxidation number of carbon in CH₂Cl₂ is
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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