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In the electrolysis of water, one faraday of electrical energy would evolve
Options
(a) one mole of oxygen
(b) one g atom of oxygen
(c) 8 g of oxygen
(d) 22.4 litres of oxygen
Correct Answer:
8 g of oxygen
Explanation:
Hydrolysis of water can be represented by the following equations: 2H₂O ⇌ O₂ + 4H⁺ + 4e⁻. 4 Faraday of charge liberate O₂ = 32 g. Therefore 1 Faraday of charge liberate O₂ = 32/4 = 8g.
Related Questions: - During the electrolysis of H₂O, volume of H₂ and O₂ are released in the ratio
- 116 mg of a compound on vaporisation in a Victor Meyer’s apparatus displaces
- Which has maximum number of molecules
- For the reaction R → P a graph of [R] against time is found to be a straight
- Of the following reaction, only one is a redox reaction.Identify this reaction
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- During the electrolysis of H₂O, volume of H₂ and O₂ are released in the ratio
- 116 mg of a compound on vaporisation in a Victor Meyer’s apparatus displaces
- Which has maximum number of molecules
- For the reaction R → P a graph of [R] against time is found to be a straight
- Of the following reaction, only one is a redox reaction.Identify this reaction
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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