| ⇦ |
| ⇨ |
₉₂U²³⁴ has 92 protons and 238 nucleons. It decays by emitting an alpha particle and becomes
Options
(a) ₉₂U²³⁴
(b) ₉₀Th²³⁴
(c) ₉₂U²³⁵
(d) ₉₃Np²³⁷
Correct Answer:
₉₀Th²³⁴
Explanation:
Emission of alpha particle, decreases the mass number by 4 and charge number by 2.
.·. Decrease in mass number = 238 – 4 = 234
Decrease in charge number = 92 – 2 = 90 ₉₀Th²³⁴ is emitted.
Related Questions: - The radius of germanium nuclide is measured to be twice the radius of ₄⁹Be.
- A tuned amplifier circuit is used to generate a carrier frequency of 2 MHz
- Equal charge q each are placed at the vertices AQ and B of an equilateral triangle
- A solid sphere, disc and solid cylinder all of the same mass and made up of same material
- A solid sphere is rotating in free space.If the radius of the sphere is increased
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The radius of germanium nuclide is measured to be twice the radius of ₄⁹Be.
- A tuned amplifier circuit is used to generate a carrier frequency of 2 MHz
- Equal charge q each are placed at the vertices AQ and B of an equilateral triangle
- A solid sphere, disc and solid cylinder all of the same mass and made up of same material
- A solid sphere is rotating in free space.If the radius of the sphere is increased
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply