⇦ | ⇨ |
A proton is projected with a speed of 3×10⁶ m/s horizontally from east to west. An uniform magnetic field of strength 2×10⁻³ T exist in the vertically upward direction. What would be the acceleration of proton?
Options
(a) 11.6×10¹¹ m/ s²
(b) 17.4×10¹¹ m/ s
(c) 5.8×10¹¹ m/ s²
(d) 2.9×10¹¹ m/ s²
Correct Answer:
5.8×10¹¹ m/ s²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The surface temperature of the sun which has maximum energy
- There is a ring of radius r having linear charge densityλ and rotating with a uniform
- If a gymnast, sitting on a rotating stool with his arms outstretched, suddenly
- When a mass M is attached to a spring of force constant K,
- A solid sphere is rotating in free space.If the radius of the sphere is increased
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The surface temperature of the sun which has maximum energy
- There is a ring of radius r having linear charge densityλ and rotating with a uniform
- If a gymnast, sitting on a rotating stool with his arms outstretched, suddenly
- When a mass M is attached to a spring of force constant K,
- A solid sphere is rotating in free space.If the radius of the sphere is increased
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply