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A proton is projected with a speed of 3×10⁶ m/s horizontally from east to west. An uniform magnetic field of strength 2×10⁻³ T exist in the vertically upward direction. What would be the acceleration of proton?
Options
(a) 11.6×10¹¹ m/ s²
(b) 17.4×10¹¹ m/ s
(c) 5.8×10¹¹ m/ s²
(d) 2.9×10¹¹ m/ s²
Correct Answer:
5.8×10¹¹ m/ s²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The photoelectric threshold wevelength for potassium (work function being 2 eV) is
- The friction of the air causes a vertical retardation equal to 10%
- The threshold frequency for a metallic surface corresponds to an energy of 6.2 eV,
- For a cubic crystal structure which one of the following relations
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The photoelectric threshold wevelength for potassium (work function being 2 eV) is
- The friction of the air causes a vertical retardation equal to 10%
- The threshold frequency for a metallic surface corresponds to an energy of 6.2 eV,
- For a cubic crystal structure which one of the following relations
- In which of the follows decays, the element does not change?
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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