| ⇦ |
| ⇨ |
A proton is projected with a speed of 3×10⁶ m/s horizontally from east to west. An uniform magnetic field of strength 2×10⁻³ T exist in the vertically upward direction. What would be the acceleration of proton?
Options
(a) 11.6×10¹¹ m/ s²
(b) 17.4×10¹¹ m/ s
(c) 5.8×10¹¹ m/ s²
(d) 2.9×10¹¹ m/ s²
Correct Answer:
5.8×10¹¹ m/ s²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A body of mass 2 kg is kept by pressing to a vertical wall by a force of 100 N
- Energy of photon whose frequency is 10¹² MHz will be
- A simple pendulum oscillates in a vertical plane. When it passes through the mean
- A wire of length 1 m is moving at a speed of 2 ms⁻¹ perpendicular to its length
- If h is Planck’s constant, the momentum of a photon of wavelength 0.01 Å is
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body of mass 2 kg is kept by pressing to a vertical wall by a force of 100 N
- Energy of photon whose frequency is 10¹² MHz will be
- A simple pendulum oscillates in a vertical plane. When it passes through the mean
- A wire of length 1 m is moving at a speed of 2 ms⁻¹ perpendicular to its length
- If h is Planck’s constant, the momentum of a photon of wavelength 0.01 Å is
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply