| ⇦ | 
| ⇨ |
Strong reducing behaviour of H₃PO₂ is due to
Options
(a) high electron gain enthalpy of phosphorus
(b) high oxidation state of phosphorus
(c) presence of two –OH groups and one P–H bond
(d) presence of one –OH group and two P–H bonds
Correct Answer:
presence of one –OH group and two P–H bonds
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Which is difference between melting and boiling point of zero group elements
- In which process,fused sodium hydroxide is eletrolysed at a 330⁰C temperature
- 100 mL each of 0.5 N NaOH, N/5 HCl and N/10 H₂SO₄ are mixed together
- According to law of mass action rate of a chemical reaction is proportional to
- Oxidation number of carbon in CH₂Cl₂ is
Topics: P Block Elements in Group 15
(89)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which is difference between melting and boiling point of zero group elements
- In which process,fused sodium hydroxide is eletrolysed at a 330⁰C temperature
- 100 mL each of 0.5 N NaOH, N/5 HCl and N/10 H₂SO₄ are mixed together
- According to law of mass action rate of a chemical reaction is proportional to
- Oxidation number of carbon in CH₂Cl₂ is
Topics: P Block Elements in Group 15 (89)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply