| ⇦ |
| ⇨ |
Strong reducing behaviour of H₃PO₂ is due to
Options
(a) high electron gain enthalpy of phosphorus
(b) high oxidation state of phosphorus
(c) presence of two –OH groups and one P–H bond
(d) presence of one –OH group and two P–H bonds
Correct Answer:
presence of one –OH group and two P–H bonds
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Which one of the following statements is not correct for ortho and para hydrogen?
- Glass is soluble in
- Oxidation number of iron in [Fe(CN)₆]⁴⁻ is
- Which one of the following pairs is isostructural – same shape and hybridization
- Ratio of Cᵥ and Cᵥ of the gas X is 1.4. The number of atoms of the gas X present
Topics: P Block Elements in Group 15
(89)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one of the following statements is not correct for ortho and para hydrogen?
- Glass is soluble in
- Oxidation number of iron in [Fe(CN)₆]⁴⁻ is
- Which one of the following pairs is isostructural – same shape and hybridization
- Ratio of Cᵥ and Cᵥ of the gas X is 1.4. The number of atoms of the gas X present
Topics: P Block Elements in Group 15 (89)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply