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A particle is executing SHM along a straight line. Its velocities at distances x₁ and x₂ from the mean position are V₁ and V₂ respectively. Its time period is
Options
(a) 2π√x₂²-x₁²/V₁²-V₂²
(b) 2π√V₁²+V₂²/x₂²+x₁²
(c) 2π√V₁²-V₂²/x₁²-x₂²
(d) 2π√x₁²-x₂²/V₁²-V₂²
Correct Answer:
2π√x₂²-x₁²/V₁²-V₂²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Oscillations
(58)
Subject: Physics
(2479)
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