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The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV, respectively. In the nuclear reaction ₃⁷Li+₁¹H→ ₂⁴He+ ₂⁴He+Q, the value of energy Q released is
Options
(a) 19.6 MeV
(b) (-24 MeV)
(c) 8.4 MeV
(d) 17.3 MeV
Correct Answer:
17.3 MeV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The equation of state for 5 g of oxygen at a pressure P and temperature T,
- A sample of HCl gas is placed in an electric field of 5 x 10⁴ N/C
- A body under the action of a force F⃗ = 6i⃗–8j⃗+10k⃗, acquires an accelerationof 1 m/s². The mass of this body must be
- A small angled prism of refractive index 1.4 is combined with another small angled prism
- In which of the following systems will the radius of the first orbit (n=1) be minimum?
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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