| ⇦ | 
| ⇨ |
In the electrolysis of aqueous solution of CuSO₄ using copper electrodes, the process that takes place at the anode is
Options
(a) SO₄²⁻ → SO₄ +2e⁻
(b) Cu → Cu⁺ + e⁻
(c) 2OH⁻ → H₂O + 1/2 O₂ + 2e⁻
(d) Cu → Cu²⁺ + 2e⁻
Correct Answer:
Cu → Cu²⁺ + 2e⁻
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Which of the following represents correct decreasing order of polarity?
- Which of the following has highest pH value with water
- If avagadro number is changed what changes
- The type of hybridisation of boron in diboron is
- Diazo-coupling is useful to prepare some
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following represents correct decreasing order of polarity?
- Which of the following has highest pH value with water
- If avagadro number is changed what changes
- The type of hybridisation of boron in diboron is
- Diazo-coupling is useful to prepare some
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply