⇦ | ⇨ |
How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide
Options
(a) 1
(b) 2
(c) 3
(d) 4
Correct Answer:
3
Explanation:
Iodine is liberated from potassium iodide.
K₂Cr₂O₇ + 4H₂SO₄ → K₂ SO₄+ Cr₂(SO₄)₃ + 4H₂O+ 3[O]
[2KI + H₂SO₄+[O] → K₂ SO₄ + I₂ +H₂O] ⨯ 3 /
[ K₂Cr₂O₇ + 6KI + 7H₂ SO₄ → 4K₂ SO₄+ Cr₂(SO₄)₃ + 7H₂O + 3I₂].
Related Questions: - Mohr’s salt is
- In an equilibrium reaction, if temperature increases
- Li occupies higher position in the electrochemical series of metals as compared
- Which one of the following is not an aldose
- Bleaching powder is obtained by treating Cl₂ with
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Mohr’s salt is
- In an equilibrium reaction, if temperature increases
- Li occupies higher position in the electrochemical series of metals as compared
- Which one of the following is not an aldose
- Bleaching powder is obtained by treating Cl₂ with
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply