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The phase difference between two points seperated by 0.8 m in a wave of frequency 120 Hz is 0.5 π. The wave velocity is
Options
(a) 144 m/s
(b) 256 m/s
(c) 384 m/s
(d) 720 m/s
Correct Answer:
384 m/s
Explanation:
Phase difference = 2π/λ × Path difference
0.5π = 2π/λ × 0.8 m or λ = (2π × 0.8 m) / 0.5π = 3.2 m
Velocity v = frequency (ʋ) × Wavelength (λ)
= 120 Hz × 3.2 m = 384 m/s.
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A black body radiates 20 W at temperature 227⁰C. It temperature of the black body
- The value of coefficient of volume expansion of glycerin is 5 x 10⁻⁴ k⁻¹.
- A current I ampere flows along the inner conductor of a co-axial cable and returns
- Four identical rods are joined to from a square. If the temperature difference
- Two charged particles have charges and masses in the ratio 2:3 and 1:4 respectively.
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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