| ⇦ |
| ⇨ |
The phase difference between two points seperated by 0.8 m in a wave of frequency 120 Hz is 0.5 π. The wave velocity is
Options
(a) 144 m/s
(b) 256 m/s
(c) 384 m/s
(d) 720 m/s
Correct Answer:
384 m/s
Explanation:
Phase difference = 2π/λ × Path difference
0.5π = 2π/λ × 0.8 m or λ = (2π × 0.8 m) / 0.5π = 3.2 m
Velocity v = frequency (ʋ) × Wavelength (λ)
= 120 Hz × 3.2 m = 384 m/s.
Related Questions: - A black body radiates 20 W at temperature 227⁰C. It temperature of the black body
- The value of coefficient of volume expansion of glycerin is 5 x 10⁻⁴ k⁻¹.
- A current I ampere flows along the inner conductor of a co-axial cable and returns
- Four identical rods are joined to from a square. If the temperature difference
- Two charged particles have charges and masses in the ratio 2:3 and 1:4 respectively.
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A black body radiates 20 W at temperature 227⁰C. It temperature of the black body
- The value of coefficient of volume expansion of glycerin is 5 x 10⁻⁴ k⁻¹.
- A current I ampere flows along the inner conductor of a co-axial cable and returns
- Four identical rods are joined to from a square. If the temperature difference
- Two charged particles have charges and masses in the ratio 2:3 and 1:4 respectively.
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply