| ⇦ | 
| ⇨ |
The phase difference between two points seperated by 0.8 m in a wave of frequency 120 Hz is 0.5 π. The wave velocity is
Options
(a) 144 m/s
(b) 256 m/s
(c) 384 m/s
(d) 720 m/s
Correct Answer:
384 m/s
Explanation:
Phase difference = 2π/λ × Path difference
0.5π = 2π/λ × 0.8 m or λ = (2π × 0.8 m) / 0.5π = 3.2 m
Velocity v = frequency (ʋ) × Wavelength (λ)
= 120 Hz × 3.2 m = 384 m/s.
Related Questions: - A long straight wire of radius a carries a steady current I. The current is uniformly
- Dimensional formula for electrical resistance R is given by
- An inductor 20 mH, a capacitor 50 μF and a resistor 40Ω are connected in series
- Two wheels having radii in the ratio 1:3 are connected by a common belt
- Electric field intensity at a point in between two parallel sheets due to like
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A long straight wire of radius a carries a steady current I. The current is uniformly
- Dimensional formula for electrical resistance R is given by
- An inductor 20 mH, a capacitor 50 μF and a resistor 40Ω are connected in series
- Two wheels having radii in the ratio 1:3 are connected by a common belt
- Electric field intensity at a point in between two parallel sheets due to like
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply