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In Young’s double slit experiment, the slit seperation is 1 mm and the screen is 1 m from the slit. For a monochromatic light of wavelength 500 nm, the distance of 3rd minima from the central maxima is
Options
(a) 0.50 mm
(b) 1.25 mm
(c) 1.50 mm
(d) 1.75 mm
Correct Answer:
1.25 mm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Sodium has body centred packing. Distance between two nearest atoms is 3.7 Å.
- A particle free to move along X-axis has potential energy given as U(X) =k(1-e⁻ˣ²)
- A satellite is revolving around the earth with a kinetic energy E. The minimum
- The electric current in AC circuit is given by the relation i-3 sinωt+4 cos ωt.
- For a cubic crystal structure which one of the following relations
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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