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In an interference experiment, third bright fringe is obtained at a point on the screen with a light of 700 nm. What should be the wavelength of the light source in order to obtain 5th bright firnge at the same point?
Options
(a) 500 nm
(b) 630 nm
(c) 750 nm
(d) 420 nm
Correct Answer:
420 nm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the minimum energy of photons needed to produce photoelectrons is 3 eV,
- If two soap bubbles of different radii are connected by a tube
- Magnetic susceptibility of a material is given as
- The ratio of amplitude of magnetic field to the amplitude of electric field for
- The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4.
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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