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In an interference experiment, third bright fringe is obtained at a point on the screen with a light of 700 nm. What should be the wavelength of the light source in order to obtain 5th bright firnge at the same point?
Options
(a) 500 nm
(b) 630 nm
(c) 750 nm
(d) 420 nm
Correct Answer:
420 nm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The resistance of a carbon resistor of colour code Red-Red Green Silver is(in kΩ)
- If rope of lift breaks suddenly, the tension exerted by the surface of the lift
- A bus is moving with a velocity of 5 ms⁻¹ towards a huge wall.
- The Davisson- Germer experiment is the direct evidence of
- A coil of resistance 10 Ω and an inductance 5 H is connected to a 100 volt
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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