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In an interference experiment, third bright fringe is obtained at a point on the screen with a light of 700 nm. What should be the wavelength of the light source in order to obtain 5th bright firnge at the same point?
Options
(a) 500 nm
(b) 630 nm
(c) 750 nm
(d) 420 nm
Correct Answer:
420 nm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The work function for aluminium is 4.125 eV. The cutoff wavelength for photoelectric
- Which of the following does not increase regularly?
- A galvanometer having internal resistance 10Ω requires 0.01 A for a full scale
- A solid sylinder of mass 3 kg is rolling on a horizontal surface with velocity 4 ms⁻¹
- The ratio of specific charge of an α-particle to that of a proton is
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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