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In an interference experiment, third bright fringe is obtained at a point on the screen with a light of 700 nm. What should be the wavelength of the light source in order to obtain 5th bright firnge at the same point?
Options
(a) 500 nm
(b) 630 nm
(c) 750 nm
(d) 420 nm
Correct Answer:
420 nm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A coil of 40 henry inductance is connected in series with a resistance of 8 ohm
- The intermediate image formed by the objective of a compound microscope is
- The resultant of two forces, one double the other in magnitude, is perpendicular
- A uniform wire of resistance 9Ω is joined end-to-end to form a circle. Then
- The transverse nature of electromagnetic waves is proved by which of the following?
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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