| ⇦ | 
| ⇨ |
In Young’s experiment, the ratio of maximum to minimum intensities of the fringe system is 4:1. The amplitudes of the coherent sources are in the ratio
Options
(a) (4:1)
(b) (3:1)
(c) (2:1)
(d) (1:1)
Correct Answer:
(3:1)
Explanation:
I(max) / I(min) = (ɑ₁ + ɑ₂)² / (ɑ₁ – ɑ₂)²
⇒ 4 / 1 = (ɑ₁ + ɑ₂)² / (ɑ₁ – ɑ₂)²
⇒ (ɑ₁ + ɑ₂) / (ɑ₁ – ɑ₂) = 2 / 1
⇒ ɑ₁ + ɑ₂ = 2 (ɑ₁ – ɑ₂)
⇒ 3ɑ₂ = ɑ₁
⇒ ɑ₁ / ɑ₂ = 3 / 1 = 3 : 1
Related Questions: - A step-down transformer has 50 turns on secondary and 1000 turns on primary winding.
- A block of mass m1 rests on a horizontal table. A light string connected
- A gas is suddenly expanded such that its final volume becomes 3 times
- In the Young’s double slit experiment, a point P on the central bright fringe
- Which of the following quantities has units but not dimensions
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A step-down transformer has 50 turns on secondary and 1000 turns on primary winding.
- A block of mass m1 rests on a horizontal table. A light string connected
- A gas is suddenly expanded such that its final volume becomes 3 times
- In the Young’s double slit experiment, a point P on the central bright fringe
- Which of the following quantities has units but not dimensions
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply