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In Young’s experiment, the ratio of maximum to minimum intensities of the fringe system is 4:1. The amplitudes of the coherent sources are in the ratio
Options
(a) (4:1)
(b) (3:1)
(c) (2:1)
(d) (1:1)
Correct Answer:
(3:1)
Explanation:
I(max) / I(min) = (ɑ₁ + ɑ₂)² / (ɑ₁ – ɑ₂)²
⇒ 4 / 1 = (ɑ₁ + ɑ₂)² / (ɑ₁ – ɑ₂)²
⇒ (ɑ₁ + ɑ₂) / (ɑ₁ – ɑ₂) = 2 / 1
⇒ ɑ₁ + ɑ₂ = 2 (ɑ₁ – ɑ₂)
⇒ 3ɑ₂ = ɑ₁
⇒ ɑ₁ / ɑ₂ = 3 / 1 = 3 : 1
Related Questions: - The value of Poisson’s ratio lies between
- Ratio of the radii of the nuclei with mass numbers 8 and 27 would be
- In a common emitter transistor amplifier, the voltage gain is
- Two coherent sources of different intensities send waves which interfere.
- The slope of the graph showing the variation of potential difference V on X-axis
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The value of Poisson’s ratio lies between
- Ratio of the radii of the nuclei with mass numbers 8 and 27 would be
- In a common emitter transistor amplifier, the voltage gain is
- Two coherent sources of different intensities send waves which interfere.
- The slope of the graph showing the variation of potential difference V on X-axis
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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