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The condition for obtaining secondary maxima in the diffraction pattern due to single slit is
Options
(a) a sin θ=nλ/2
(b) a sin θ=(2n-1)λ/2
(c) a sin θ=nλ
(d) a sin θ=(2n-1)λ
Correct Answer:
a sin θ=(2n-1)λ/2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Which is correct relation?
- The total energy of a particle executing SHM is 80 J
- In Young’s double slit interference experiment, using two coherent waves
- In n-type semiconductor, electrons are majority charge carriers
- Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which is correct relation?
- The total energy of a particle executing SHM is 80 J
- In Young’s double slit interference experiment, using two coherent waves
- In n-type semiconductor, electrons are majority charge carriers
- Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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