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The intensity at the maximum in a Young’s double slit experiment is I₀. Distance between two slits is d=5λ, where λ is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance, D= 10 d?
Options
(a) I₀/4
(b) 3/4 I₀
(c) I₀/2
(d) I₀
Correct Answer:
I₀/2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two thin lenses when placed in contact, then the power of combination is +10 D.
- A particle moves along the x-axis such that its co-ordinate (x) varies with time (t)
- A boy whirls a stone in a horizontal circle of radius 1.5 m and at height 2.0 m
- Given the value of Rydberg constant is 10⁷ m⁻¹, the wave number of the last line
- A body is hangfing from a rigid support by an inextensible string of length
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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