⇦ | ![]() | ⇨ |
The energy required to charge a parallel plate condenser of plate separation d and plate area of cross-section A such that the uniform electric field between the plates is E, is
Options
(a) ε₀E² Ad
(b) 1/2 ε₀E² Ad
(c) 1/2 ε₀E²/ Ad
(d) ε₀E² /Ad
Correct Answer:
1/2 ε₀E²/ Ad
Explanation:
The energy required to charge a parallel plate condenser is given by U = 1/2 CV²
As C =ε₀ A / d and V = E.d
U = 1/2ε₀ A / d . E²d²
= 1/2ε₀ E² Ad
Related Questions:
- A proton and an alpha particle both enter a region of uniform magnetic field B,
- A certain number of spherical dropes of a liquid of radius r coalesce to form a single
- In a given process on an ideal gas, dW=0 and dQ<0. Then for the gas
- A particle executing simple harmonic motion of amplitude 5 cm has maximum
- If two electric bulbs have 40 W and 60 W ratings at 220 V, then the ratio
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply