| ⇦ |
| ⇨ |
Two electrons are separated by a distance of 1Å. What is the coulomb force between them?
Options
(a) 2.3×10⁻⁸ N
(b) 4.6×10⁻⁸ N
(c) 1.5×10⁻⁸ N
(d) None of these
Correct Answer:
2.3×10⁻⁸ N
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A heavy nucleus at rest breaks into two fragments which fly off with velocities
- A spring of spring constant 5 x 10³ N/m is stretched initially by 5 cm
- Starting from the origin, a body oscillates simple harmonically with a period of 2s
- Equal charge q each are placed at the vertices AQ and B of an equilateral triangle
- A deutron is bombarded on ₈O¹⁶ nucleus and α-particle is emitted. The product nucleus is
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A heavy nucleus at rest breaks into two fragments which fly off with velocities
- A spring of spring constant 5 x 10³ N/m is stretched initially by 5 cm
- Starting from the origin, a body oscillates simple harmonically with a period of 2s
- Equal charge q each are placed at the vertices AQ and B of an equilateral triangle
- A deutron is bombarded on ₈O¹⁶ nucleus and α-particle is emitted. The product nucleus is
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

1 angstrom = 10^-10 metre.
Also,electron charge=1.6 X 10^-19
F=1/4π€.(q1 X q2)/r^2
thus,
F=(9X10^9) X (1.6X10^-19)^2/(10^-10 X 10^-10)
Hence,F = 23.04 X 10^-9
Implies,F = 2.3 X 10^-8 N