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In a common emitter (CE) amplifier having a voltage gain G, the transistor used has transconductance 0.03 mho and current gain 25. If the above transistor is replaced with another one with transconductance 0.02 mho and current gain 20, the voltage gain will be
Options
(a) 1.5 G
(b) 1/3 G
(c) 5/4 G
(d) 2/3 G
Correct Answer:
2/3 G
Explanation:
Voltage gain ∆ᵥ = β Rₒᵤₜ / Rᵢₙ
G = 25 Rₒᵤₜ / Rᵢₙ ….(i)
Transconductance gₘ = β / Rᵢₙ
Rᵢₙ = β / gₘ = 25 / 0.03
Puttin g this value of Rᵢₙ in eqn.(i)
G = 25 Rₒᵤₜ / 25 x 0.03 …(ii)
G’ = 20 Rₒᵤₜ / 20 x 0.02 …(iii)
From eqs. (ii) and (iii)
Voltage gain of new transistor G’ = 2/3 G
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Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two nuclei have their mass numbers into the ratio of 1:3
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- One way in which the operation of a n-p-n transistor differs from that of a p-n-p
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- If we study the vibration of a pipe open at both ends
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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