| ⇦ | 
| ⇨ |
If the self inductance of 500 turn coil is 125 mH, then the self inductance of similar coil of 800 turns is
Options
(a) 48.4 mH
(b) 200 mH
(c) 187.5 mH
(d) 320 mH
Correct Answer:
320 mH
Explanation:
Self inductance of a coil, L = μᵣμ₀n² Al
Where μᵣ is the relative permittivity of the coil, n is the number of terms per unit length, A is the area of cross-section, l is the length of the solenoid
L ∝ n²
Self inductance of 500 turns coil = 125 mH Therefore, L for the coil of 800 turns = [125 / (500)²] × 800² L = 320 mH
Related Questions: - The loudness and pitch of a sound note depends on
- Dimensions of electrical resistance are
- If the ionisation energy for the hydrogen atom is 13.6 eV, the energy required
- The electirc field in a certain region is acting radially outward and is given by E=Ar.
- A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s. The work
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The loudness and pitch of a sound note depends on
- Dimensions of electrical resistance are
- If the ionisation energy for the hydrogen atom is 13.6 eV, the energy required
- The electirc field in a certain region is acting radially outward and is given by E=Ar.
- A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s. The work
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply