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The phase difference between the flux linked with a coil rotating in a uniform magnetic field and induced emf produced in it is
Options
(a) π/2
(b) π/3
(c) (-π/6)
(d) π
Correct Answer:
π/2
Explanation:
The flux ɸ = B.A = |B| |A| cos θ
Also, induced emf, ε = – (dɸ / dt) = (d |B| |A| cos θ) / dt
= – |B| |A| [d cos θ / dt] = |B| |A| sin θ. ω
ε = BA ω cos [θ – (π / 2)]
Related Questions: - A 36 Ω galvanometer is shunted by resistance of 4 Ω. The percentage of the total current
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A 36 Ω galvanometer is shunted by resistance of 4 Ω. The percentage of the total current
- The dimensional formula of Plancks’s constant and angular momentum are
- The flux linked with a coil at any intant t is given by ?=10t² – 50t + 250
- A particle of masses m is thrown upwards from the surface of the earth, with a velocity u
- Curie temperature above which
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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