Young’s modulus of the material of a wire is 18×10¹¹ dyne cm⁻².its value in SI is

⇦

⇨

Young’s modulus of the material of a wire is 18 x 10¹¹ dyne cm⁻². Its value in SI is

Options

(a) 18 x 10¹⁵ Nm⁻²
(b) 18 x 10¹⁰ Nm⁻²
(c) 18 x 10⁹ Nm⁻²
(d) 18 x 10¹² Nm⁻²

Correct Answer:

18 x 10¹⁰ Nm⁻²

Explanation:

1 dyne = 10⁻⁵ Newton

1 cm  = 10⁻² m

So, 18 x 10¹¹ x 10⁻⁵ / 10⁻⁴ 

=18 x 10¹⁰ Nm⁻²

Related Questions:

1. A particle of mass M is executing oscillations about the origin on the x-axis.
2. The kinetic energy of particle moving along a circle of radius R depends
3. The masses of three wires of copper are in the ratio 1:3:5 and lengths
4. An electron moving in a uniform magnetic field of induction of intensity B,
5. Which of the following rods of same material undergoes maximum elongation

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends