Young’s modulus of the material of a wire is 18×10¹¹ dyne cm⁻².its value in SI is

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Young’s modulus of the material of a wire is 18 x 10¹¹ dyne cm⁻². Its value in SI is

Options

(a) 18 x 10¹⁵ Nm⁻²
(b) 18 x 10¹⁰ Nm⁻²
(c) 18 x 10⁹ Nm⁻²
(d) 18 x 10¹² Nm⁻²

Correct Answer:

18 x 10¹⁰ Nm⁻²

Explanation:

1 dyne = 10⁻⁵ Newton

1 cm  = 10⁻² m

So, 18 x 10¹¹ x 10⁻⁵ / 10⁻⁴ 

=18 x 10¹⁰ Nm⁻²

Related Questions:

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2. In Young’s double slit experiment, a third slit is made in between the double slits.
3. Find the right condition(s) for Fraunhofer diffraction due to a single slit.
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5. The first line in Lyman series has wavelength λ. The wavelength

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)

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