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Young’s modulus of the material of a wire is 18 x 10¹¹ dyne cm⁻². Its value in SI is
Options
(a) 18 x 10¹⁵ Nm⁻²
(b) 18 x 10¹⁰ Nm⁻²
(c) 18 x 10⁹ Nm⁻²
(d) 18 x 10¹² Nm⁻²
Correct Answer:
18 x 10¹⁰ Nm⁻²
Explanation:
1 dyne = 10⁻⁵ Newton
1 cm = 10⁻² m
So, 18 x 10¹¹ x 10⁻⁵ / 10⁻⁴
=18 x 10¹⁰ Nm⁻²
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Question Type: Memory
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Difficulty Level: Easy
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second
- For a series L-C-R circuit, the rms values of voltage across various components
- Sodium and copper have work function 2.3 eV and 4.5 eV respectively
- The mass of a lift is 2000kg. When the tension in the supporting cable is 28000N, then its acceleration is
- Which of the following phenomena does not show the wavenature of light?
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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