| ⇦ |
| ⇨ |
Work done by an external agent in separating the parallel plate capacitor is
Options
(a) CV
(b) 1/2 C²V
(c) 1/2 CV²
(d) None of these
Correct Answer:
1/2 CV²
Explanation:
Energy stored in capacitor = (1/2) CV²
External agent should apply (1/2) CV² energy for separating the plates.
Related Questions: - The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field
- A circular disc of radius 0.2 meter is placed in a uniform magnetic field of induction
- If the band gap between valence band and conduction band in a material is 5.0 eV,
- In an L-C-R series resonant circuit, the capacitance is changed from C to 4C.
- Two parallel long wires carry currents i₁ and i₂ with i₁ > i₂ .
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The dimension of 1/2ε₀E², where ε₀ is permittivity of free space and E is electric field
- A circular disc of radius 0.2 meter is placed in a uniform magnetic field of induction
- If the band gap between valence band and conduction band in a material is 5.0 eV,
- In an L-C-R series resonant circuit, the capacitance is changed from C to 4C.
- Two parallel long wires carry currents i₁ and i₂ with i₁ > i₂ .
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply