| ⇦ | 
| ⇨ |
With the decrease of current in the primary coil from 2 amperes to zero value in 0.01sec, the emf generated in the secondary coil is 1000 volts. The mutual inductance is
Options
(a) 1.25 H
(b) 2.50 H
(c) 5 H
(d) 10 H
Correct Answer:
5 H
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The tension in a piano wire is 10 N. What should be the tension in the wire to produce
- Four indentical thin rods each of mass M and length l, form a square frame
- At which place, Earth’s magnetism becomes horizontal
- A beam of electron passes undeflected through mutually perpendicular
- In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The tension in a piano wire is 10 N. What should be the tension in the wire to produce
- Four indentical thin rods each of mass M and length l, form a square frame
- At which place, Earth’s magnetism becomes horizontal
- A beam of electron passes undeflected through mutually perpendicular
- In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply