| ⇦ | 
| ⇨ |
Which would exhibit ionisation isomerism
Options
(a) [Co(NH₃)₄] [Cr(C₂O₄)₃]
(b) [CoBr(NH₃)₅]²⁺SO₄²⁻
(c) [CoBr(NH₃)₅]
(d) K₃(Fe(CN)₆]
Correct Answer:
[CoBr(NH₃)₅]²⁺SO₄²⁻
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The pH value of 0.02 M ammonia solution, which is 5% ionised, will be
- The latest technique for the purification of organic concept is
- A bromoalkane contains 35% carbon and 6.57% hydrogen by mass. Calculate the empirical
- Which of the following gases has the lowest value of Henry’s law constant
- If the energy of a photon is given as : =3.03 × 10⁻¹⁹J then, the wavelength (λ)
Topics: Coordination Compounds
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The pH value of 0.02 M ammonia solution, which is 5% ionised, will be
- The latest technique for the purification of organic concept is
- A bromoalkane contains 35% carbon and 6.57% hydrogen by mass. Calculate the empirical
- Which of the following gases has the lowest value of Henry’s law constant
- If the energy of a photon is given as : =3.03 × 10⁻¹⁹J then, the wavelength (λ)
Topics: Coordination Compounds (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply