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Which of the following will not undergo Hell-Volhard-Zelinsky reaction
Options
(a) Acetic acid
(b) Formic acid
(c) Propionic acid
(d) 2-Methyl propionic acid
Correct Answer:
Formic acid
Explanation:
Carboxylic acid which contain α – hydrogen atom reacts with chlorine or bromine in presence of red phosphorus to give α – chloro or α – bromo acids. This reaction is called H.V.Z (Hell Volhard Zelinsky ) reaction. CH₃COOH → CCl₃COOH(trichloroacetic acid). CH₃CH₂COOH → CH₃CBr₂COOH (α,α-dibromopropionic acid) Due to absence of α – H atom HCOOH does not undergo HVZ reaction.
Related Questions: - How will you separate a solution (miscible) of benzene + CHCl₃
- If 0.1 M of a weak acid is taken, and its percentage of degree of ionization
- An organic compound contains 49.3% carbon,6.84% hydrogen and its vapour density
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Topics: Aldehydes Ketones and Carboxylic Acid
(89)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- How will you separate a solution (miscible) of benzene + CHCl₃
- If 0.1 M of a weak acid is taken, and its percentage of degree of ionization
- An organic compound contains 49.3% carbon,6.84% hydrogen and its vapour density
- Equivalent weight of KMnO₄ in basic medium is (mol.wt. of KMnO₄ = 158)
- Which one of the following electrolytes has the same value of van’t Hoff’s factor
Topics: Aldehydes Ketones and Carboxylic Acid (89)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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