| ⇦ | 
| ⇨ |
When ₃Li⁷ nuclei are bombarded by protons, and the resultant nuclei are ₄Be⁸, the emitted particles will be
Options
(a) neutrons
(b) alpha particles
(c) beta particles
(d) gamma photons
Correct Answer:
gamma photons
Explanation:
₃Li⁷ + ₁H¹ → ₂Be⁴ + zX ᴬ
Z for the unknown X nucleus = 3 + 1 – 4 = 0
A for the unknown X nucleus = 7 + 1 – 8 = 0
Hence particle emitted has zero Z and zero A
It is a gamma photon.
Related Questions: - In case of linearly polarised light, the magnitude of the electric field vector
- The flux linked with a coil at any intant t is given by ?=10t² – 50t + 250
- If sound wave travel from air to water, which of the following remains unchanged?
- Surface tension of a solution is 30 x 10⁻² N/m. The radius of the soap bubble is 5 cm
- A solid sphere is rotating in free space.If the radius of the sphere is increased
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In case of linearly polarised light, the magnitude of the electric field vector
- The flux linked with a coil at any intant t is given by ?=10t² – 50t + 250
- If sound wave travel from air to water, which of the following remains unchanged?
- Surface tension of a solution is 30 x 10⁻² N/m. The radius of the soap bubble is 5 cm
- A solid sphere is rotating in free space.If the radius of the sphere is increased
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply