| ⇦ |
| ⇨ |
When you move from equator to pole, the value of acceleration due to gravity (g)
Options
(a) Increases
(b) Decreases
(c) Remains the same
(d) Increases then decreases
Correct Answer:
Increases
Explanation:
g’=g-Rω². cos²λ
λ=0 at equator and 90° at poles
ge’=g-Rω²,gp’=g
g increases from equator to pole.
Related Questions: - A particle is moving with a uniform velocity along a straight line path
- The component of vector A=2i+3j along the vector i+j is
- What is the energy released by fission of 1 g of U²³⁵?
- Force required to move a mass of 1kg at rest on a horizontal rough plane
- In a circuit, the current lags behind the voltage by a phase difference of π/2.
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle is moving with a uniform velocity along a straight line path
- The component of vector A=2i+3j along the vector i+j is
- What is the energy released by fission of 1 g of U²³⁵?
- Force required to move a mass of 1kg at rest on a horizontal rough plane
- In a circuit, the current lags behind the voltage by a phase difference of π/2.
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply