| ⇦ | 
| ⇨ |
When ethyl alcohol (C₂H₅OH) reacts with thionyl chloride in the presence of pyridine the product obtained is
Options
(a) CH₃CH₂Cl + HCl
(b) CH₃CH₂Cl + H₂O + SO₂
(c) CH₃CH₂Cl + Cl₂ + SO₂
(d) C₂H₅Cl + HCl + SO₂
Correct Answer:
C₂H₅Cl + HCl + SO₂
Explanation:
C₂H₅OH + SOCl₂ → C₂H₅Cl + HCl + SO₂.
Related Questions: - Secondary amines could be prepared by
- The compound which does not exist as hydrate form
- Amongst the elements with following electronic configurations
- If the melting point of ice is 0⁰C and latent heat of fusion is 5.46 kJ mol⁻¹,
- In the following reaction reducing agent is
2K₃[Fe(CN)₆]+H₂O₂+2KOH→2K₄[Fe(CN)₆]
Topics: Haloalkenes and Haloarenes
(78)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Secondary amines could be prepared by
- The compound which does not exist as hydrate form
- Amongst the elements with following electronic configurations
- If the melting point of ice is 0⁰C and latent heat of fusion is 5.46 kJ mol⁻¹,
- In the following reaction reducing agent is 2K₃[Fe(CN)₆]+H₂O₂+2KOH→2K₄[Fe(CN)₆]
Topics: Haloalkenes and Haloarenes (78)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply