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When a metallic surface is illuminated with radiation of wavelength λ, the stopping potential is V. If the same surface is illuminating with radiation of wavelength 2λ, the stopping potential is V/4. The threshold wavelength for the metallic surface is
Options
(a) 5λ
(b) 5/2 λ
(c) 3λ
(d) 4λ
Correct Answer:
3λ
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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