| ⇦ | 
| ⇨ |
What will be the ratio of the distance moved by a freely falling body from rest in 4th and 5th seconds of journey?
Options
(a) 4 : 5
(b) 7 : 9
(c) 16 : 25
(d) 1 : 1
Correct Answer:
7 : 9
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The velocity of electromagnetic radiation in a medium of permittivity ε₀
- A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 secs
- when a magnetic field is applied on a stationary electron, then it
- Angle of contact of a liquid with a solid depends on
- The ratio of the numerical value of the average velocity and average speed
Question Type: Apply
(15)
Difficulty Level: Easy
(1008)
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The velocity of electromagnetic radiation in a medium of permittivity ε₀
- A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 secs
- when a magnetic field is applied on a stationary electron, then it
- Angle of contact of a liquid with a solid depends on
- The ratio of the numerical value of the average velocity and average speed
Question Type: Apply (15)
Difficulty Level: Easy (1008)
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
By using,
Snth=u+a/2 (2n-1)=0+a/2 (2×4-1)=7a/2
Again,s=u+a/2 (2n-1)=0+a/2 (2×5-1)=9a/2
Now,S1:S2=7a/2:9a/2=7:9