| ⇦ | 
| ⇨ |
What will be the partial pressure of He and O₂, if 200 mL of He at 0.66 atm and 400 mL of O₂ at 0.52 atm. pressure are mixed in 400 mL vessel at 20⁰C
Options
(a) 0.33 and 0.52
(b) 0.33 and 0.55
(c) 0.25 and 0.45
(d) 0.38 and 0.52
Correct Answer:
0.33 and 0.52
Explanation:
Pʜₑ = (200 × 0.66) / 400 = 0.33 atm
Po₂ = (400 × 0.52) / 400 = 0.52 atm.
Related Questions: - If n = 6, the correct sequence for filling of electrons will be:
- The activation energy of a reaction can be determined from the slope
- The most probable radius (in pm) for finding the electron in He⁺ is
- At 27⁰C average kinetic energy of one mole of helium gas can be given
- In the following reaction reducing agent is
2K₃[Fe(CN)₆]+H₂O₂+2KOH→2K₄[Fe(CN)₆]
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If n = 6, the correct sequence for filling of electrons will be:
- The activation energy of a reaction can be determined from the slope
- The most probable radius (in pm) for finding the electron in He⁺ is
- At 27⁰C average kinetic energy of one mole of helium gas can be given
- In the following reaction reducing agent is 2K₃[Fe(CN)₆]+H₂O₂+2KOH→2K₄[Fe(CN)₆]
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply