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Unit of reduction factor is
Options
(a) ampere
(b) ohm
(c) tesla
(d) weber
Correct Answer:
ampere
Explanation:
Reduction factor K = i/tan θ
.·. i = K tanθ
The unit of current (i) is ampere. So, the unit of reduction factor (K) is equivalent to that of current (i).
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Question Type: Memory
(964)
Difficulty Level: Easy
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Topics: Physical World and Measurement
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The numebr 0 (zero) is required for
- A condenser of 250 μF is connected in parallel to a coil of inductance of 0.16 mH
- For the radioactive nuclei that undergo either α or β decay, which one
- An iron rod of volume 10⁻⁴ m³ and relative permeability 1000 is placed inside a long
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Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Reduction factor of say Tangent Galvanometer is actually numerically equal to the current in ampere needed to produce a deflection of 45° when plane of coil lies in magnetic meridian
K=Itan(theta). I has unit ampere and (theta) is the ratio b/w opposite side and adjacent side so length by length. therefore tan (theta) has no unit. So unit of K is Ampere.