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Two resistors of 6Ω and 9Ω are connected in series to a 120 V source. The power consumed by 6Ω resistor is
Options
(a) 384Ω
(b) 616Ω
(c) 1500Ω
(d) 1800Ω
Correct Answer:
384Ω
Explanation:
Equivalent resistance in series = 6 + 9 = 15 Ω
Current flow in circuit, i = V / R = 120 / 15 = 8 A
Voltage in 6Ω resistor, V = iR = 8 × 6 = 48 V
Power consumed by 6Ω resistor,
P = V² / R = (48 × 48) / 6 = 8 × 48 = 384 W
Related Questions: - Out of the following which pair of quantities does not have same dimensions?
- The charge flowing through a resistance R varies with time t as Q=at-bt²,
- A galvanometer of resistance 50Ω is connected to a battery of 3 V along with a resistance
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Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Out of the following which pair of quantities does not have same dimensions?
- The charge flowing through a resistance R varies with time t as Q=at-bt²,
- A galvanometer of resistance 50Ω is connected to a battery of 3 V along with a resistance
- The threshold wavelength for photoelectric effect of a metal is 6500 Å. The work function
- As per Bohr model, the minimum energy (in eV) required to remove an electron
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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