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Two particles of masses m₁ m₂ move with initial velocities u₁ and u₂ .On collision, one of the particle s get excited to higher level, after absorbing energy E.If final velocities of particles be v₁ and v₂, then we must have
Options
(a) m₁²u₁+ m₂²u₂ -E = m₁²v₁+ m₂²v₂
(b) 1/2 m₁u₁²+m₂ u₂² = 1/2 m₁v₁²+ 1/2 m₂v₂² -E
(c) 1/2 m₁u₁²+m₂ u₂² -E = 1/2 m₁v₁²+ 1/2 m₂v₂²
(d) 1/2 m₁u₁²+m₂ u₂² +E = 1/2 m₁v₁²+ 1/2 m₂v₂²
Correct Answer:
1/2 m₁u₁²+m₂ u₂² -E = 1/2 m₁v₁²+ 1/2 m₂v₂²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A tuning fork of frequency 512 Hz makes 4 beats per second with the vibrating string
- A uniform rod of length l is placed with one end in contact with the horizontal
- The half life of radium is about 1600 year. Of 100 gram of radium existing now
- The work function of a substance is 4.0 eV. The longest wavelength of light
- If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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