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Two genes R and Y are located very close on the chromosomal linkage map of maize plant. When RRYY and rryy genotypes are hybridized, the F₂ segregation will show
Options
(a) segregation in the expected 9 : 3 : 3 : 1 ratio
(b) segregation in 3 : 1 ratio
(c) higher number of the parental types
(d) higher number of the recombinant types.
Correct Answer:
higher number of the parental types
Explanation:
When the linked genes are situated quite close, the chances of crossing over are highely reduced. Due to this, large number of parental gametes are formed and only few recombinant gametes are formed. This results in higher no. of parental types in F₂ generation as compared to recombinations.
Related Questions: - In the light of recent classification of living organisms into three domains
- Which one of the following proved effective for biological control of nematodal
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Topics: Genetics
(204)
Subject: Biology
(4253)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the light of recent classification of living organisms into three domains
- Which one of the following proved effective for biological control of nematodal
- Which one of the following represents a palindromic sequence in DNA?
- Formation of RBC’s in the bone marrow is called
- Calorific value for carbohydrates, proteins and fats is
Topics: Genetics (204)
Subject: Biology (4253)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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