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Two bodies of masses m₁ and m₂ are initially at rest at infinite distance apart.They are then allowed to move towards each other under mutual gravitational attraction with the escape velocity .Their relative velocity of approach at a separation distance r between them is
Options
(a) [2 G(m₁- m₂ )/r]¹/²
(b) [2 G(m₁+m₂ )/r]¹/²
(c) [r/2G(m₁m₂)]¹/²
(d) [2G / r(m₁m₂)]¹/²
Correct Answer:
[2 G(m₁+m₂ )/r]¹/²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- To convert a 800 mV range millivoltmeter of resistance 40Ω into an ammeter of 100 mA
- For inelastic collision between two spherical rigid bodies
- In Young’s double slit experiment, a third slit is made in between the double slits.
- Three objects A,B and C are kept in a straight line on a frictionless horizontal surface
- A change of 0.04 V takes place between the base and the emitter when an input
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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