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Two bodies of masses m₁ and m₂ are initially at rest at infinite distance apart.They are then allowed to move towards each other under mutual gravitational attraction with the escape velocity .Their relative velocity of approach at a separation distance r between them is
Options
(a) [2 G(m₁- m₂ )/r]¹/²
(b) [2 G(m₁+m₂ )/r]¹/²
(c) [r/2G(m₁m₂)]¹/²
(d) [2G / r(m₁m₂)]¹/²
Correct Answer:
[2 G(m₁+m₂ )/r]¹/²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - An ideal gas is compressed to half its initial volume by means of several processes.
- In Wheatstone bridge, three resistors P,Q and R are conncected in three arms
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An ideal gas is compressed to half its initial volume by means of several processes.
- In Wheatstone bridge, three resistors P,Q and R are conncected in three arms
- The molar specific heats of an ideal gas at constant pressure and volume are denoted
- If we study the vibration of a pipe open at both ends
- Two point white dots are 1 mm apart on a black paper.
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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