Three particles A,B and C are thrown from the top of a tower with the same speed.

Three particles A,B and C are thrown from the top of a tower with the same speed. A is thrown straight up, B is thrown straight down and C is thrown horizontally. They hit the ground with speed V(A),V(B) and V(C) respectively.

Options

(a) V(A)=V(B)=V(C)
(b) V(B)>V(C)>V(A)
(c) V(A)=V(B)>V(C)
(d) V(A)>V(B)=V(C)

Correct Answer:

V(A)=V(B)>V(C)

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

admin:

Related Questions

  1. Electron in hydrogen atom first jumps from third excited state to second excited
  2. A bar magnet with magnetic moment 2.5×10³ JT⁻¹ is rotating in horizontal plane
  3. The wavelength of the first line of Lymasn series for hydrogen atom is equal
  4. An adiabatic process occurs at constant
  5. The velocity of radio-waves is 3×10⁵ km/s. The frequency corresponding to wavelength