Navigate

Three particles A,B and C are thrown from the top of a tower with the same speed.

Three particles A,B and C are thrown from the top of a tower with the same speed. A is thrown straight up, B is thrown straight down and C is thrown horizontally. They hit the ground with speed V(A),V(B) and V(C) respectively.

Options

(a) V(A)=V(B)=V(C)
(b) V(B)>V(C)>V(A)
(c) V(A)=V(B)>V(C)
(d) V(A)>V(B)=V(C)

Correct Answer:

V(A)=V(B)>V(C)

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

DCE2006
admin:

Related Questions

  1. Two bodies of masses m₁ and m₂ are initially at rest at infinite distance apart
  2. When a current of (2.5±0.5) A flows through a wire, it develops a potential difference
  3. The horizontal and vertical components of earth’s magnetic field at a place
  4. Energy of all molecules of a monoatomic gas having a volume V and pressure P is 3PV/2.
  5. A microscope is having objective of focal length 1 cm and eye-piece of focal length 6 cm.