| ⇦ | 
| ⇨ |
Three particles A,B and C are thrown from the top of a tower with the same speed. A is thrown straight up, B is thrown straight down and C is thrown horizontally. They hit the ground with speed V(A),V(B) and V(C) respectively.
Options
(a) V(A)=V(B)=V(C)
(b) V(B)>V(C)>V(A)
(c) V(A)=V(B)>V(C)
(d) V(A)>V(B)=V(C)
Correct Answer:
V(A)=V(B)>V(C)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In a given process on an ideal gas, dW=0 and dQ<0. Then for the gas
- The amount of heat energy required to raise the temperature of 1 g of Helium
- Three objects A,B and C are kept in a straight line on a frictionless horizontal surface
- If ∆U and ∆W represent the increase in internal energy and work done by the system
- When a charged oil drop moves upwards in an electric field,
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a given process on an ideal gas, dW=0 and dQ<0. Then for the gas
- The amount of heat energy required to raise the temperature of 1 g of Helium
- Three objects A,B and C are kept in a straight line on a frictionless horizontal surface
- If ∆U and ∆W represent the increase in internal energy and work done by the system
- When a charged oil drop moves upwards in an electric field,
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply