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Three capacitors of capacitances 3 μF, 10 μF and 15 μF are connected in series to a voltage source of 100V. The charge on 15 μF is
Options
(a) 500 μC
(b) 100 μC
(c) 200 μC
(d) 280 μC
Correct Answer:
200 μC
Explanation:
Equivalent capacitance = C
1/C = 1/3 + 1/10 + 1/15 = (10 + 3 + 2) / 30 = 15 / 30 = 1 / 2
⇒ C = 2 μF
Charge through each capacitor is same as they are joined in series.
Q = CV = 2 × 100 = 200 μC
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Topics: Electrostatics
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If in a L-R series circuit the power factor is 1/2 and R=100Ω, then the value of L is,
- A metal bar of length L and area of cross-section A is clamped between two rigid
- A galvanometer acting as a voltmeter will have
- In communication with help of antenna if height is doubled then the range
- A thin film of soap solution (n=1.4) lies on the top of a glass plate (n=1.5).
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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