| ⇦ | 
| ⇨ |
The work of 146 kJ is performed in order to compress one kilo mole fo gas adiabatically and in this process the temperature of the gas increases by 7⁰C. The gas is (R=8.3 J mol⁻¹ K⁻¹)
Options
(a) Monoatomic
(b) Diatomic
(c) Triatomic
(d) A mixture of monoatomic and diatomic
Correct Answer:
Diatomic
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A body has 80 microcoulomb of charge. Number of additional electrons in it will be
- An α-particle moves in a circular path of radius 0.83 cm in the presence of a magnetic
- The angular velocity of second’s hand of a watch is
- The energy released by the fission of one uranium atom is 200 MeV.
- Energy of photon whose frequency is 10¹² MHz will be
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body has 80 microcoulomb of charge. Number of additional electrons in it will be
- An α-particle moves in a circular path of radius 0.83 cm in the presence of a magnetic
- The angular velocity of second’s hand of a watch is
- The energy released by the fission of one uranium atom is 200 MeV.
- Energy of photon whose frequency is 10¹² MHz will be
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply