| ⇦ | 
| ⇨ |
The volume occupies by one molecules of water is [density of water =1g/cm³
Options
(a) 22400 cm³
(b) 6.02 ˣ 10⁻²³cm³
(c) 3.0 ˣ 10⁻²³cm³
(d) 11200cm³
Correct Answer:
3.0 ˣ 10⁻²³cm³
Explanation:
Given density of water = 1 g/cm³, Therefore 1 g of H₂O₂ = 1 cm³ of H₂O, 1 mole of water = 18 g of H₂O = 18 cm³ of H₂O, Therefore , 6.022 ˣ 10²³ molecule of water occupy volume = 18 ml, Therefore 1 molecule of water occupy volume = 18 / 6.022 ˣ 10²³ = 2.99 ˣ 10⁻²³.
Related Questions: - Which of the following statement regarding hydrogen peroxide is false
- Elements having same number of nucleons and different number of protons are
- If the gas at constant temperature and pressure expands, then its
- Of the following which one is classified as polymer
- In diborane the two H-B-H angles are nearly
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following statement regarding hydrogen peroxide is false
- Elements having same number of nucleons and different number of protons are
- If the gas at constant temperature and pressure expands, then its
- Of the following which one is classified as polymer
- In diborane the two H-B-H angles are nearly
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply