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The volume occupies by one molecules of water is [density of water =1g/cm³
Options
(a) 22400 cm³
(b) 6.02 ˣ 10⁻²³cm³
(c) 3.0 ˣ 10⁻²³cm³
(d) 11200cm³
Correct Answer:
3.0 ˣ 10⁻²³cm³
Explanation:
Given density of water = 1 g/cm³, Therefore 1 g of H₂O₂ = 1 cm³ of H₂O, 1 mole of water = 18 g of H₂O = 18 cm³ of H₂O, Therefore , 6.022 ˣ 10²³ molecule of water occupy volume = 18 ml, Therefore 1 molecule of water occupy volume = 18 / 6.022 ˣ 10²³ = 2.99 ˣ 10⁻²³.
Related Questions: - The correct order of electron affinity is
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Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The correct order of electron affinity is
- Be resembles much with
- Which of the following is expected not to yield a white precipitate
- When 25g of Na₂SO₄ is dissolved in 10³ kg of solution,its concentration will be
- Only sp and sp² hybrid orbitals are involved in the formation of
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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