| ⇦ | 
| ⇨ |
The total radiant energy per unit area, normal to the direction of incidence, received at a distance R from the centre of a star of radius r, whose outer surface radiates as a black body at a temperature T K is given by: (where σ is Stefan’s constant)
Options
(a) σr²T⁴ / R²
(b) σr²T⁴ / 4πr²
(c) σr⁴T⁴ / r⁴
(d) 4π σr²T⁴ / R²
Correct Answer:
σr²T⁴ / R²
Explanation:
E = S / S₀ σT⁴ = 4πr² / 4πR² σT⁴
σr²T⁴ / R²
Related Questions: - The temperature of a metal block is increased from 27⁰C to 84⁰C. The rate of radiated energy
- Order of e/m ratio of proton, α-particle and electron is
- The unit of thermal conductivity is
- A scooter is going round a circular road of radius 100 m at a speed of 10m/s
- The atomic number of the most common element in nuclear fusion is
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The temperature of a metal block is increased from 27⁰C to 84⁰C. The rate of radiated energy
- Order of e/m ratio of proton, α-particle and electron is
- The unit of thermal conductivity is
- A scooter is going round a circular road of radius 100 m at a speed of 10m/s
- The atomic number of the most common element in nuclear fusion is
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply