| ⇦ | 
| ⇨ |
The total energy of a particle executing SHM is 80 J. What is the potential energy when the particle is at a distance of 3/4 of amplitude from mean position
Options
(a) 60 J
(b) 10 J
(c) 40 J
(d) 45 J
Correct Answer:
45 J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The instantaneous angular position of a point on a rotating wheel is given by
- The second overtone of an open pipe is in resonance with the first overtone
- The distance travelled by a particle starting from rest and moving with an acceleration
- A 1Ω resistance in series with an ammeter is balanced by 75 cm of potentiometer wire
- Two closed pipes produce 10 beats per second when emitting their fundamental nodes.
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The instantaneous angular position of a point on a rotating wheel is given by
- The second overtone of an open pipe is in resonance with the first overtone
- The distance travelled by a particle starting from rest and moving with an acceleration
- A 1Ω resistance in series with an ammeter is balanced by 75 cm of potentiometer wire
- Two closed pipes produce 10 beats per second when emitting their fundamental nodes.
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
U = 80 sin2 x sin-3/4
= 80 x 9
————–
16
=45 J