| ⇦ | 
| ⇨ |
The total energy of a particle executing SHM is 80 J. What is the potential energy when the particle is at a distance of 3/4 of amplitude from mean position
Options
(a) 60 J
(b) 10 J
(c) 40 J
(d) 45 J
Correct Answer:
45 J
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If in a nuclear fusion process, the masses of the fusing nuclei be m₁ and m₂
- If particles are moving with same velocity, then maximum de Broglie wavelength will
- If the binding energy of the electron in a hydrogen atom is 13.6 eV, the energy
- A round uniform body of radius R, mass M and moment of inertia I rolls down
- Which of the following is true for number of spectral lines in going from Lyman series
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If in a nuclear fusion process, the masses of the fusing nuclei be m₁ and m₂
- If particles are moving with same velocity, then maximum de Broglie wavelength will
- If the binding energy of the electron in a hydrogen atom is 13.6 eV, the energy
- A round uniform body of radius R, mass M and moment of inertia I rolls down
- Which of the following is true for number of spectral lines in going from Lyman series
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
U = 80 sin2 x sin-3/4
= 80 x 9
————–
16
=45 J