The ratio of longest wavelength corresponding to Lyman and Blamer series

The Ratio Of Longest Wavelength Corresponding To Lyman And Blamer Physics QuestionThe Ratio Of Longest Wavelength Corresponding To Lyman And Blamer Physics Question

The ratio of longest wavelength corresponding to Lyman and Blamer series in hydrogen spectrum is

Options

(a) 3 / 23
(b) 7 / 29
(c) 9 / 13
(d) 5 / 27

Correct Answer:

5 / 27

Explanation:

For Lyman series (2 → 1)
1/λL = R [1 – 1/2] = 3R/4
For Balmer series (3 → 2)
1/λB = R [1/4 – 1/9] = 5R/36
λL / λB = 4/3R / 36/5R = 4/36 (5/3) = 5/27

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