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The ratio of area covered by second orbital to the first orbital is
Options
(a) 1 : 2
(b) 1 : 16
(c) 8 : 1
(d) 16 : 1
Correct Answer:
16 : 1
Explanation:
r(n) ∝ n² ; A(n) ∝ n⁴.
A₂ / A₁ = n₂⁴ / n⁴₁ = 2⁴ / 1⁴ = 16 / 1.
Related Questions: - How many grams of dibasic acid (mol.wt.200) should be present in 100 mL.
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Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- How many grams of dibasic acid (mol.wt.200) should be present in 100 mL.
- The range of radius ratio (cationic to anionic) for an octahedral arrangement
- Which of the following will show a negative deviation from Raoult’s law
- Which compound is zero valent metal complex
- Among the following pairs of ions, the lower oxidation state in aqueous solution
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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